8x^2+4+8=29

Solution for 8x^2+4+8=29 equation:

8x^2+4+8=29

We move all terms to the left:

8x^2+4+8-(29)=0

We add all the numbers together, and all the variables

8x^2-17=0

a = 8; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·8·(-17)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{34}}{2*8}=\frac{0-4\sqrt{34}}{16}
=-\frac{4\sqrt{34}}{16}
=-\frac{\sqrt{34}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{34}}{2*8}=\frac{0+4\sqrt{34}}{16}
=\frac{4\sqrt{34}}{16}
=\frac{\sqrt{34}}{4}
$